Hi
Could somebody help me solve this question
(a) Express the following statements in logarithmic notation:3.375= 2.25 3/2
That's 3over2 . Thanks so much
cypress, what skeeter wrote was not an "answer" but the basic relationship between a logarithm and an exponential. It is impossible to give an answer to the problem you posted because you clearly did not post it correctly- there is no exponent in what you gave so it can't be converted to logarithms. Did you mean to write 3.375= 2.25^(3/2)?
If you have to solve this exercice then I thought you would know some rules about logarithms. But have you tried something with the rules I mentioned?
$\displaystyle \log(3,375)=\log(2,25^{\frac{3}{2}})$
$\displaystyle \Leftrightarrow \log(3,375)=\frac{3}{2}\log(2,25)$ (is this clear?)
$\displaystyle \Leftrightarrow \frac{\log(3,375)}{\log(2,25)}=\frac{3}{2}$
Now, apply the last rule I mentioned.
in your original post, you started with an exponential equation ...
$\displaystyle 3.375 = 2.25^{3/2}$
... and were asked to change it to an equation using logarithmic notation
$\displaystyle \log_{2.25}(3.375) = \frac{3}{2}$
that's all.