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Math Help - logarithmic notation

  1. #1
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    Thumbs up logarithmic notation

    Hi

    Could somebody help me solve this question
    (a) Express the following statements in logarithmic notation:3.375= 2.25 3/2
    That's 3over2 . Thanks so much
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  2. #2
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    Re: logarithmic notation

    Quote Originally Posted by cypress View Post
    Hi

    Could somebody help me solve this question
    (a) Express the following statements in logarithmic notation:3.375= 2.25 3/2
    That's 3over2 .
    a = b^c

    c = \log_b{a}
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  3. #3
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    Re: logarithmic notation

    Thanks

    But I don't understand how you got that answer...could you break it down?
    I would be very greatful.Thanks
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  4. #4
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    Re: logarithmic notation

    Quote Originally Posted by cypress View Post
    Thanks

    But I don't understand how you got that answer...could you break it down?
    I would be very greatful.Thanks
    Logarithms: Introduction to "The Relationship"
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  5. #5
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    Re: logarithmic notation

    Quote Originally Posted by skeeter View Post
    Thank you so much!!!
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  6. #6
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    Re: logarithmic notation

    cypress, what skeeter wrote was not an "answer" but the basic relationship between a logarithm and an exponential. It is impossible to give an answer to the problem you posted because you clearly did not post it correctly- there is no exponent in what you gave so it can't be converted to logarithms. Did you mean to write 3.375= 2.25^(3/2)?
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  7. #7
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    Re: logarithmic notation

    Quote Originally Posted by HallsofIvy View Post
    cypress, what skeeter wrote was not an "answer" but the basic relationship between a logarithm and an exponential. It is impossible to give an answer to the problem you posted because you clearly did not post it correctly- there is no exponent in what you gave so it can't be converted to logarithms. Did you mean to write 3.375= 2.25^(3/2)?
    Yes thats what i was trying to workout. Wolud you mind showing me how it's done?
    Thanks
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  8. #8
    MHF Contributor Siron's Avatar
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    Re: logarithmic notation

    Take the logarithm of both sides, therefore:
    \log(3,375)=\log(2,25^{\frac{3}{2}})
    Now use the following rules to continue:
    \log(a^b)=b\log(a)
    \frac{\log(b)}{\log(a)}=\log_a(b)
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  9. #9
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    Re: logarithmic notation

    Quote Originally Posted by Siron View Post
    Take the logarithm of both sides, therefore:
    \log(3,375)=\log(2,25^{\frac{3}{2}})
    Now use the following rules to continue:
    \log(a^b)=b\log(a)
    \frac{\log(b)}{\log(a)}=\log_a(b)
    Hi

    I'm new to logarithms,unsure how to do the next step. Can you show me or do you know a link I could learn from?

    Thanks so much
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  10. #10
    MHF Contributor Siron's Avatar
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    Re: logarithmic notation

    If you have to solve this exercice then I thought you would know some rules about logarithms. But have you tried something with the rules I mentioned?
    \log(3,375)=\log(2,25^{\frac{3}{2}})
    \Leftrightarrow \log(3,375)=\frac{3}{2}\log(2,25) (is this clear?)
    \Leftrightarrow \frac{\log(3,375)}{\log(2,25)}=\frac{3}{2}

    Now, apply the last rule I mentioned.
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  11. #11
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    Re: logarithmic notation

    Tha much is clear, can't grasp the concept of the next step :-(
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  12. #12
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    Re: logarithmic notation

    in your original post, you started with an exponential equation ...

    3.375 = 2.25^{3/2}

    ... and were asked to change it to an equation using logarithmic notation

    \log_{2.25}(3.375) = \frac{3}{2}

    that's all.
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  13. #13
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    Re: logarithmic notation

    I can understand it when I see it broken down, I find it difficult to know what rules to use.
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