Having some troubles figuring out these two logarithmic equations
First is 4^m+2=32
And the second is
6^2-r=50
Thanks in advance would love to know how to solve
I suppose you mean ...
$\displaystyle 4^{m+2} = 32$
you can solve this equation w/o logs ... note that $\displaystyle 4 = 2^2$ and $\displaystyle 32 = 2^5$
$\displaystyle 6^{2-r} = 50$
$\displaystyle \log(6^{2-r}) = \log(50)$
use the power property of logarithms and finish it ...