Simple Algebra Question

**dubs1013** · October 18th 2011, 03:08 PM

Hi Everyone,

I was hoping for some help on the following problem

44000 * (1.03)^x = 50000 * (1.02)^x

What does X equal?

Thanks in advance,
Chris

**TheEmptySet** · October 18th 2011, 03:15 PM

Originally Posted by dubs1013

Hi Everyone,

I was hoping for some help on the following problem

44000 * (1.03)^x = 50000 * (1.02)^x

What does X equal?

Thanks in advance,
Chris

You can simplify the equation to

$\left( \frac{1.03}{1.02} \right)^x=\frac{25}{22}$

You can use a logarithm to finish solving from here.

**dubs1013** · October 18th 2011, 03:52 PM

If you could walk me through the logarihm that would be great. Thank you very much

**skeeter** · October 18th 2011, 04:12 PM

$a^x = b$

$\log(a^x) = \log(b)$

$x \log(a) = \log(b)$

$x = \frac{\log(b)}{\log(a)}$

Thread: Simple Algebra Question