# I'm asking for help to show the working out of an aptitude test example

• October 17th 2011, 02:20 PM
Yarbles
I'm asking for help to show the working out of an aptitude test example
Hi all, I’m finding in a lot of job interviews I’m required to complete some basic aptitude tests so I’ve been checking out some examples online for practice and come across this example.

A=5
B=0
C=2
D=10
E=2
What is then AB + EE - (ED)B + (AC)E =

The answer is 103 but I’ve no idea how it was reached, getting to the 50+22 is easy enough but as soon as I hit the brackets I’m totally lost
I’m just looking for an explanation on how it was worked out and I apologize in advance if I’ve posted this in the wrong thread.

Imageshack - unledecz.png
BTW here’s a screenshot of how it was expressed on the example.
• October 17th 2011, 02:40 PM
emakarov
Re: I'm asking for help to show the working out of an aptitude test example
Does AB mean the product of A and B or something else?
• October 17th 2011, 03:09 PM
Yarbles
Re: I'm asking for help to show the working out of an aptitude test example
I don’t know to be honest I’ve no more info to offer other than that screenshot I posted, I’m just reading those letters as straight out representations of their allotted numbers until I see a + or –

Does (ED)B mean 210x0 or 12x0 ? That’s assuming the those brackets indicate that the value within has to be multiplied with B which is 0
I’m totally and utterly confused (Worried)
• October 17th 2011, 03:13 PM
SammyS
Re: I'm asking for help to show the working out of an aptitude test example
Quote:

Originally Posted by Yarbles
Hi all, I’m finding in a lot of job interviews I’m required to complete a basic aptitude tests so I’ve been checking out some examples online for practice and come across this example.

A=5, B=0, C=2, D=10, E=2

What is then AB + EE - (ED)^B + (AC)^E =
...

Notice that B and E should be exponents. I've corrected the in the "Quote" above.

It looks better in LaTeX:

$B + EE - (ED)^B + (AC)^E$

Did you know the any non-zero number raised to the zero power is 1 ?
• October 17th 2011, 04:10 PM
Yarbles
Re: I'm asking for help to show the working out of an aptitude test example
Thanks SammyS for your help, you’ve put me on the right track and I’ve now found some easy to understand tutorials regarding exponentiation.
• October 17th 2011, 05:34 PM
Yarbles
Re: I'm asking for help to show the working out of an aptitude test example
I've worked it out
5x0 = 0 + 2x2 = 4 -
(20)^0 1 = 3
+
(10)^2 = 100

3 + 100 = 103

103 = Correctamundo

This is just a personal bugbear, but why didn’t they give clear instructions to multiply the AB, EE and so on , after all they did give clear instructions to both + and – (Headbang)

So once again thanks very much emakarov & SammyS