Results 1 to 3 of 3

Math Help - Solving this equation

  1. #1
    Newbie
    Joined
    Oct 2011
    Posts
    2

    Solving this equation

    Can anyone help me solve this basic equation (including the steps). I know the answer, I just don't know how to get there.

    5^9x+2 = (1/25)^2x-9

    Excuse the format, don't know how to do exponents on this forum.

    Thanks a lot.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    -1
    e^(i*pi)'s Avatar
    Joined
    Feb 2009
    From
    West Midlands, England
    Posts
    3,053
    Thanks
    1

    Re: Solving this equation

    Quote Originally Posted by Burbujas View Post
    Can anyone help me solve this basic equation (including the steps). I know the answer, I just don't know how to get there.

    5^9x+2 = (1/25)^2x-9

    Excuse the format, don't know how to do exponents on this forum.

    Thanks a lot.
    I assume the question is 5^{9x+2} = \left(\dfrac{1}{25}\right)^{2x-9}

    Note that \dfrac{1}{25} = 5^{-2} so the RHS becomes 5^{-2(2x-9)}

    If two bases are the same then their exponents must be the same: 9x+2 = -2(2x-9). Solve for x
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Oct 2011
    Posts
    2

    Re: Solving this equation

    Oh wow, that was so simple. I got it now, thanks a lot.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. solving an equation
    Posted in the Algebra Forum
    Replies: 1
    Last Post: December 5th 2011, 12:35 AM
  2. Solving Tri equation
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: December 7th 2009, 06:26 PM
  3. Solving an equation
    Posted in the Algebra Forum
    Replies: 2
    Last Post: February 29th 2008, 09:16 AM
  4. solving diff equation w/ bournoulli's equation
    Posted in the Calculus Forum
    Replies: 2
    Last Post: February 14th 2008, 06:06 PM
  5. Help on solving equation
    Posted in the Algebra Forum
    Replies: 1
    Last Post: July 26th 2007, 04:01 PM

Search Tags


/mathhelpforum @mathhelpforum