# Math Help - Solving this equation

1. ## Solving this equation

Can anyone help me solve this basic equation (including the steps). I know the answer, I just don't know how to get there.

5^9x+2 = (1/25)^2x-9

Excuse the format, don't know how to do exponents on this forum.

Thanks a lot.

2. ## Re: Solving this equation

Originally Posted by Burbujas
Can anyone help me solve this basic equation (including the steps). I know the answer, I just don't know how to get there.

5^9x+2 = (1/25)^2x-9

Excuse the format, don't know how to do exponents on this forum.

Thanks a lot.
I assume the question is $5^{9x+2} = \left(\dfrac{1}{25}\right)^{2x-9}$

Note that $\dfrac{1}{25} = 5^{-2}$ so the RHS becomes $5^{-2(2x-9)}$

If two bases are the same then their exponents must be the same: $9x+2 = -2(2x-9)$. Solve for x

3. ## Re: Solving this equation

Oh wow, that was so simple. I got it now, thanks a lot.