Can anyone help me solve this basic equation (including the steps). I know the answer, I just don't know how to get there.
5^9x+2 = (1/25)^2x-9
Excuse the format, don't know how to do exponents on this forum.
Thanks a lot.
I assume the question is $\displaystyle 5^{9x+2} = \left(\dfrac{1}{25}\right)^{2x-9}$
Note that $\displaystyle \dfrac{1}{25} = 5^{-2}$ so the RHS becomes $\displaystyle 5^{-2(2x-9)}$
If two bases are the same then their exponents must be the same: $\displaystyle 9x+2 = -2(2x-9)$. Solve for x