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Math Help - Finding Cube root

  1. #1
    Senior Member vaironxxrd's Avatar
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    Finding Cube root

    Problem: \sqrt[3]{\frac{8a^3}{27b^6}}

    Solution(Wrong):

    \frac{2a\sqrta}{3\sqrt{b \cdot b \cdot b \cdot b \cdot b \cdot b}}

    \frac{2a\sqrta}{3 \cdot 3b^2}
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  2. #2
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    e^(i*pi)'s Avatar
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    Re: Finding Cube root

    Quote Originally Posted by vaironxxrd View Post
    Problem: \sqrt[3]{\frac{8a^3}{27b^6}}

    Solution(Wrong):

    \frac{2a\sqrta}{3\sqrt{b \cdot b \cdot b \cdot b \cdot b \cdot b}}

    \frac{2a\sqrta}{3 \cdot 3b^2}

    b^6 = (b^3)^2
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  3. #3
    MHF Contributor
    skeeter's Avatar
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    Re: Finding Cube root

    looks like you have one too many "3's"

    \sqrt[3]{\frac{8a^3}{27b^6}} = \frac{\sqrt[3]{8} \cdot \sqrt[3]{a^3}}{\sqrt[3]{27} \cdot \sqrt[3]{b^6}}
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