(x/(x-3))+(a/x)+(x-12)/((x^2)-3x)=0 - Wolfram|Alpha
Could someone help me with this equation, please?
(x/(x-3))+(a/x)+(x-12)/((x^2)-3x)=0 - Wolfram|Alpha
Could someone help me with this equation, please?
Your first step is to put everything over a common denominator. Factor $\displaystyle x^2-3x$ and see if you can work out what the common denominator is. Then, once you've done that, remember that the only way a fraction can be equal to $\displaystyle 0$ is if the numerator is equal to $\displaystyle 0$. This will give you an equation to solve for $\displaystyle a$.
If you require further help, please show what you can do and we'll guide you from there.
Okay, so x(x-3) is the common denominator. Which gives me (x^2 + ax-3a + x-12)/ x(x-3) =0 , or (x^2 + x(a+1) - 3(a+4))/ x(x-3).
If I solve the numerator for x, I get x=3, and x=-a-4.
Should I try to solve the equation first with x=3, and then x=-a-4?