I need help in learning how to do these two problems.
#1 (3^1/2 2^3/2)^2
#2 b^2/5 (b^8/5 + b 3/5 ) *Assuming that b is positive
I know the answer to #1 is 24 but, the only way I obtained a 24 was by:
(3^1/2 2^3/2)^2
3^1 2^3
(3) 8 = 24, but, I thought, you're suppose to square the 3 & 2 and change it into (9^1 & 4^3) I'm confused by both problems.
Can you show me both steps so I can see where I am going wrong and how to obtain the answers.