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Math Help - Simplifying radical expressions with fractions

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    Senior Member vaironxxrd's Avatar
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    Simplifying radical expressions with fractions

    I'm having a tough time with the rules of simplifying radicals with fractions.

    I don't understand why can't I reduce, -\sqrt\frac{60}{5}

    to -\sqrt\frac{12}{1}
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  2. #2
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    Re: Simplifying radical expressions with fractions

    Quote Originally Posted by vaironxxrd View Post
    I'm having a tough time with the rules of simplifying radicals with fractions.

    I don't understand why can't I reduce, -\sqrt\frac{60}{5}

    to -\sqrt\frac{12}{1}
    who said you cannot? -\sqrt{\frac{60}{5}} = -\sqrt{12} = -2\sqrt{3}
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    Senior Member vaironxxrd's Avatar
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    Re: Simplifying radical expressions with fractions

    Quote Originally Posted by skeeter View Post
    who said you cannot? -\sqrt{\frac{60}{5}} = -\sqrt{12} = -2\sqrt{3}
    I got to stop my habit of not checking my answers. Sorry for taking of your time skeeter.
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    Senior Member vaironxxrd's Avatar
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    Re: Simplifying radical expressions with fractions

    Quote Originally Posted by skeeter View Post
    who said you cannot? -\sqrt{\frac{60}{5}} = -\sqrt{12} = -2\sqrt{3}
    Skeeter if I have -\frac{9}{2\sqrt45}

    Would the solution be:

    -\frac{9}{2\sqrt{3 \cdot 3 \cdot 5}}
    =

    -\frac{9}{2 \cdot 3 \sqrt5}
    =

    -\frac{9}{6\sqrt5}

    -\frac{3}{2\sqrt5}

    -\frac{3\sqrt5}{10}
    ?
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    Re: Simplifying radical expressions with fractions

    Quote Originally Posted by vaironxxrd View Post
    Skeeter if I have -\frac{9}{2\sqrt45}

    Would the solution be:

    -\frac{9}{2\sqrt{3 \cdot 3 \cdot 5}}
    =

    -\frac{9}{2 \cdot 3 \sqrt5}
    =

    -\frac{9}{6\sqrt5}

    -\frac{3}{2\sqrt5}

    -\frac{3\sqrt5}{10}
    ?
    Yes, that's correct
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