I'm having a tough time with the rules of simplifying radicals with fractions.
I don't understand why can't I reduce, $\displaystyle -\sqrt\frac{60}{5}$
to $\displaystyle -\sqrt\frac{12}{1}$
Skeeter if I have $\displaystyle -\frac{9}{2\sqrt45}$
Would the solution be:
$\displaystyle -\frac{9}{2\sqrt{3 \cdot 3 \cdot 5}}$
=
$\displaystyle -\frac{9}{2 \cdot 3 \sqrt5}$
=
$\displaystyle -\frac{9}{6\sqrt5}$
$\displaystyle -\frac{3}{2\sqrt5}$
$\displaystyle -\frac{3\sqrt5}{10}$
?