Originally Posted by

**hachataltoolimhakova** Thanks for the response. I do not know what that means since I am not familiar with the notation. Am I correct in believing $\displaystyle (\ -5 \left \mid x \mid \left \sqrt{y})^2$ yields the same result as using 5? Again, thanks for the response. An explanation of that notation would be good. I found 'for all', that was all I could interpret.

EDIT: Ah, is it because it is the principle square root and since y is positive, 5 has to be positive? Otherwise the overall term would be negative, and it wouldn't be the prinicpal square root?