Hello forum vaironxxrd here.

I have this problem that is, a radical with two variables in it.

Problem:

Solution: =

=

Is that solution right? or what am I doing wrong?

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- Oct 14th 2011, 05:13 AMvaironxxrdSimplifying radical expressions with variables
Hello forum vaironxxrd here.

I have this problem that is, a radical with two variables in it.

Problem:

Solution: =

=

Is that solution right? or what am I doing wrong? - Oct 14th 2011, 05:20 AMPlatoRe: Simplifying radical expressions with variables
- Oct 14th 2011, 08:09 AMe^(i*pi)Re: Simplifying radical expressions with variables
- Oct 14th 2011, 09:15 AMhachataltoolimhakovaRe: Simplifying radical expressions with variables
- Oct 14th 2011, 09:37 AMPlatoRe: Simplifying radical expressions with variables
- Oct 14th 2011, 11:01 AMhachataltoolimhakovaRe: Simplifying radical expressions with variables
Thanks for the response. I do not know what that means since I am not familiar with the notation. Am I correct in believing yields the same result as using 5? Again, thanks for the response. An explanation of that notation would be good. I found 'for all', that was all I could interpret.

EDIT: Ah, is it because it is the principle square root and since y is positive, 5 has to be positive? Otherwise the overall term would be negative, and it wouldn't be the prinicpal square root? - Oct 14th 2011, 12:59 PMHallsofIvyRe: Simplifying radical expressions with variables
- Oct 14th 2011, 03:08 PMvaironxxrdRe: Simplifying radical expressions with variables
- Oct 14th 2011, 03:18 PMPlatoRe: Simplifying radical expressions with variables
- Oct 14th 2011, 03:34 PMvaironxxrdRe: Simplifying radical expressions with variables
- Oct 14th 2011, 03:40 PMPlatoRe: Simplifying radical expressions with variables
- Oct 14th 2011, 03:42 PMvaironxxrdRe: Simplifying radical expressions with variables
- Oct 18th 2011, 12:33 PMhachataltoolimhakovaRe: Simplifying radical expressions with variables
I have a dumb question. If I have the function I can have two solutions which yield non-negative numbers: for x>=0 and for x<=0. Are these valid solutions providing I state the ranges, or are they not valid because they do not satisfy all values of x? I assume the absolute value signs ensure that all values of x are valid. I was just wondering because by stating ranges for x, I can include -5 as a solution.

Thanks in advance. - Oct 18th 2011, 12:54 PMPlatoRe: Simplifying radical expressions with variables