Determine the equation in the form f(x)=1/(kx-c) for the function with a vertical asymptote at x=-1 and a y-intercept at -0.25.
I don't get how you get k or c.
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The y intercept is where .
The asymptote is a point the graph will tend towards but never reach. When will a value for not exist for ? Hint: Consider the denominator.
I got c=4 and k=-4, but so is the answer 1/(-4x-4)?
Originally Posted by Dragon08 I got c=4 and k=-4, but so is the answer 1/(-4x-4)? Looks good! You can always plot the function here to check.
Okay, thank you!
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