Determine the equation in the form f(x)=1/(kx-c) for the function with a vertical asymptote at x=-1 and a y-intercept at -0.25.

I don't get how you get k or c.

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- Oct 12th 2011, 06:47 PMDragon08Reciprocal of a Linear Function
Determine the equation in the form f(x)=1/(kx-c) for the function with a vertical asymptote at x=-1 and a y-intercept at -0.25.

I don't get how you get k or c. - Oct 12th 2011, 06:53 PMQuackyRe: Reciprocal of a Linear Function
The y intercept is where $\displaystyle x=0$.

The asymptote is a point the graph will tend towards but never reach. When will a value for $\displaystyle f(x)$ not exist for $\displaystyle x=-1$? Hint: Consider the denominator. - Oct 12th 2011, 07:51 PMDragon08Re: Reciprocal of a Linear Function
I got c=4 and k=-4, but so is the answer 1/(-4x-4)?

- Oct 12th 2011, 08:00 PMQuackyRe: Reciprocal of a Linear Function
Looks good! You can always plot the function here to check.

- Oct 13th 2011, 12:12 PMDragon08Re: Reciprocal of a Linear Function
Okay, thank you!