# Square root inside square root equation

• October 10th 2011, 03:06 PM
Remriel
Square root inside square root equation
• October 10th 2011, 03:10 PM
TheChaz
Re: Square root inside square root equation
Quote:

Originally Posted by Remriel

Square both sides.
Subtract x
Square both sides (don't forget to "FOIL"/distribute)
Subtract 5
Check for extraneous roots
• October 10th 2011, 03:12 PM
Plato
Re: Square root inside square root equation
Quote:

Originally Posted by Remriel

If $\sqrt{\sqrt{x+5}+x~}=5$ then $\sqrt{x+5}=25-x$.
Now you finish it off.
• October 10th 2011, 04:17 PM
Remriel
Re: Square root inside square root equation
Oh wow, I was making a really stupid mistake on this easy problem. Thanks.