I really did not wanted to start a new thread, but like skeeter said.a single thread with multiple problems all strung out is more annoying.

So I'm having a bit of confusion with simplifying this algebraic expression.

Problem:$\displaystyle \frac{y^1^0}{2x^3}\frac{20x^1^4}{xy^6}$

How I solved it.

$\displaystyle \frac{y^1^0}{2x^3}\frac{20x^1^4}{xy^6}$ = $\displaystyle \frac{y^1^0&20x^1^4}{2x^3&xy^6}$

= $\displaystyle \frac{y^1^020x^1^4}{2x^4y^6}$ <-- Should I also add the bases?

=$\displaystyle y^1^0^-^6& 10x^1^4^-^4$

Result:$\displaystyle y^4&10x^1^0$