Thread: Solve a cubic

I need solve this equation

Originally Posted by Mhmh96

I also need solve this equation ^

Can you find a value of x that makes the LHS = 0?

The factors of are .

Now, roots of the equation can be found.

Originally Posted by sbhatnagar

The factors of are .

Now, roots of the equation can be found.

Correct though.
@ Mhmh96

You can use factor theorem to factorize this equation : x^3+2x^2+2x+1
What are the factors of 1 ?
1 AND -1
-1 is satisfying the equation to 0
f(-1) =0
so
x+1 is factor of x^3+2x^2+2x+1
Now use division method .
Quotient will be
(1 + x + x^2)

So x^3+2x^2+2x+1 = (x+1)(1 + x + x^2)