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Math Help - Solve a cubic

  1. #1
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    Solve a cubic

    I need solve this equation

    x^3+2x^2+2x+1=0
    Last edited by CaptainBlack; October 8th 2011 at 03:53 AM.
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  2. #2
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    Re: Solve equation

    Quote Originally Posted by Mhmh96 View Post
    I also need solve this equation ^
    Can you find a value of x that makes the LHS = 0?
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  3. #3
    Member sbhatnagar's Avatar
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    Re: Solve equation

    The factors of x^3+2x^2+2x+1 are (1 + x) (1 + x + x^2).

    Now, roots of the equation can be found.
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  4. #4
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    Re: Solve equation

    Quote Originally Posted by sbhatnagar View Post
    The factors of x^3+2x^2+2x+1 are (1 + x) (1 + x + x^2).

    Now, roots of the equation can be found.
    Correct though.
    @ Mhmh96

    You can use factor theorem to factorize this equation : x^3+2x^2+2x+1
    What are the factors of 1 ?
    1 AND -1
    -1 is satisfying the equation to 0
    f(-1) =0
    so
    x+1 is factor of x^3+2x^2+2x+1
    Now use division method .
    Quotient will be
    (1 + x + x^2)

    So x^3+2x^2+2x+1 = (x+1)(1 + x + x^2)
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