Another fine day for math isn't it? Well thank you all for helping me ahead of time!
Things we know:You can jog 8 miles in the same time that it takes to travel 16 miles by car. IF the car's rate is 9 miles per hour faster than your jogging rate, find the average rate of each.
Jogging rate = X
Cars Rate = X+9
Distance jogging = 8 Miles
Distance Car = 16
We don't know over all time and general rate...
I was thinking I could take the time and set it equal to 1 and go from there so:
1=(1/8) / X : So X=1/8
(1/8) + 9 = 9.125
Is that correct? .125 and 9.125?