Are these questions right?
1. 32x^5 - 108x^2
4x^3 (8x^2 - 27)
2. 8y^6 - 38y^4 - 10y^2
2y^2 (4y^4 - 19y^2 - 5)
2y^2 (y^2 - 5)(4y^2 + 1)
Also, how would I solve:
z^5 - 32z^4 - 16z + 48
My teacher did not explain to us how to do this...
1. The HCF is 4x^2, not 4x^3...
2. Correct
3. You are expected to know that if you can find a z = a such that f(a) = 0, then (z - a) is a factor. You are also expected to know that a can only be factors of 48...
Once you have found a factor (z - a), long divide, follow the same process again with the remaining factor until it's completely factorised.