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Math Help - #2 Simplifying Radicals

  1. #1
    Member Jonboy's Avatar
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    #2 Simplifying Radicals

    Please check my work here. I like my method, I don't want fractions instead of radicals.

    The prob is: 2\sqrt[3]{8x^2}\,+\,5\sqrt[3]{27x^2}\,-\,3\sqrt{x^3}

    That simplifies to 4\sqrt[3]{x^2} +  15\sqrt[3]{x^2}\,-\,3x\sqrt{x}\;=\;\boxed{19\sqrt[3]{x^2}\,-\,3x\sqrt{x}}

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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Jonboy View Post
    Please check my work here. I like my method, I don't want fractions instead of radicals.

    The prob is: 2\sqrt[3]{8x^2}\,+\,5\sqrt[3]{27x^2}\,-\,3\sqrt{x^3}

    That simplifies to 4\sqrt[3]{x^2} +  15\sqrt[3]{x^2}\,-\,3x\sqrt{x}\;=\;\boxed{19\sqrt[3]{x^2}\,-\,3x\sqrt{x}}

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    looks fine. still don't like that the x's in the last term are in separate places, but in some sense it is simpler i guess
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  3. #3
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    Re: #2 Simplifying Radicals

    You are right , one can go a step further write the last term as square-root of x^3 for similarity.
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    Re: #2 Simplifying Radicals

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