• Sep 14th 2007, 02:06 PM
Jonboy

The prob is: $2\sqrt[3]{8x^2}\,+\,5\sqrt[3]{27x^2}\,-\,3\sqrt{x^3}$

That simplifies to $4\sqrt[3]{x^2} + 15\sqrt[3]{x^2}\,-\,3x\sqrt{x}\;=\;\boxed{19\sqrt[3]{x^2}\,-\,3x\sqrt{x}}$

Lookin' good?
• Sep 14th 2007, 02:22 PM
Jhevon
Quote:

Originally Posted by Jonboy

The prob is: $2\sqrt[3]{8x^2}\,+\,5\sqrt[3]{27x^2}\,-\,3\sqrt{x^3}$

That simplifies to $4\sqrt[3]{x^2} + 15\sqrt[3]{x^2}\,-\,3x\sqrt{x}\;=\;\boxed{19\sqrt[3]{x^2}\,-\,3x\sqrt{x}}$

Lookin' good?

looks fine. still don't like that the x's in the last term are in separate places, but in some sense it is simpler i guess
• Mar 28th 2013, 08:00 PM
ibdutt