Originally Posted by

**Jonboy** Hello everyone! I would like it very much if you all checked my work. Thank you.

My directions are: Simplify. Assume that no radicands were formed by raising a negative quantities to even powers.

My problem is: $\displaystyle \frac{\sqrt{128a^2b^4}}{\sqrt{16ab}}$

I dwindled it down to: $\displaystyle \frac{\sqrt{64\cdot 2}ab^2}{4\sqrt{ab}}\;=\;\frac{8\sqrt{2}ab^2}{4\sqr t{ab}}\;=\;\frac{2\sqrt{2}ab^2}{\sqrt{ab}}$

So now I need to rationalize the denominator right?

So I did that and got: $\displaystyle \boxed{\frac{2ab^2\sqrt{2ab}}{ab}}$

Does this look good, my math community?