You made some mistakes
Add "ax" to both sides
Subtract "9b^2" from both sides
Now divide both sides by (3b+a) to get the expression for "x"
and simplify the last line.
As the denominator cannot be zero,
the given condition is
Rearrange the following equation to find x in terms of a and b in simplest form (assume that a =/-3b)
the / should be through the = to show a is not equal to -3b
Couldnot find the key for it sorry!
3b(x+3b)=a(a-x)
3bx+9b^2=a^2-ax
(3b-a)x=a^2-9b^2
(3b-a)x=(a-3b)(a+3b)
this is where i get unsure.
I think then it becomes
(a-3b)(a+3b)
- ______________
3b-a
which then becomes
x= -(a+b)
which is x= a-b
Are my workings out right or am I completley of the mark?
Apologies for the way i may have presented my workings out still getting to grips with showing my workings out on a computer
You made some mistakes
Add "ax" to both sides
Subtract "9b^2" from both sides
Now divide both sides by (3b+a) to get the expression for "x"
and simplify the last line.
As the denominator cannot be zero,
the given condition is