Question: The equation of a straight line is 3x+2y=5. Given that the points (s,4) lies on the line, find the value of s My solution: 2y=-3x+5 y=-1.5x+2.5 4=-1.5x+2.5 x= (4-2.5)/-1.5 Therefore s= -1 Is this right? Thanks
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Originally Posted by FailInMaths Question: The equation of a straight line is 3x+2y=5. Given that the points (s,4) lies on the line, find the value of s My solution: 2y=-3x+5 y=-1.5x+2.5 4=-1.5x+2.5 x= (4-2.5)/-1.5 Therefore s= -1 Is this right? Thanks Hi FailInMaths, Yes. It is correct.
Thanks!
Note: If you substitute the point (s,4) in the equation then you get: You used in stead of which can be confusing.