Math Help - The quation of a straight line is 3x+2y=5....

1. The quation of a straight line is 3x+2y=5....

Question:
The equation of a straight line is 3x+2y=5. Given that the points (s,4) lies on the line, find the value of s

My solution:
2y=-3x+5
y=-1.5x+2.5
4=-1.5x+2.5
x= (4-2.5)/-1.5
Therefore s= -1

Is this right?

Thanks

2. Re: The quation of a straight line is 3x+2y=5....

Originally Posted by FailInMaths
Question:
The equation of a straight line is 3x+2y=5. Given that the points (s,4) lies on the line, find the value of s

My solution:
2y=-3x+5
y=-1.5x+2.5
4=-1.5x+2.5
x= (4-2.5)/-1.5
Therefore s= -1

Is this right?

Thanks
Hi FailInMaths,

Yes. It is correct.

Thanks!

4. Re: The quation of a straight line is 3x+2y=5....

Note:
If you substitute the point (s,4) in the equation then you get:
$4=\frac{3}{2}s+2,5$

You used $x$ in stead of $s$ which can be confusing.