$\displaystyle

f(x) = 2(x-3)(x+2)^2 + 2(x+2)(x-3)^3

$

Factorise f(x) completely.

Mind to tell me how I going to start to solve this ?

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- Oct 2nd 2011, 11:09 PMgilagilaFactorise Equation
$\displaystyle

f(x) = 2(x-3)(x+2)^2 + 2(x+2)(x-3)^3

$

Factorise f(x) completely.

Mind to tell me how I going to start to solve this ? - Oct 2nd 2011, 11:10 PMProve ItRe: Factorise Equation
- Oct 3rd 2011, 01:04 AMgilagilaRe: Factorise Equation
- Oct 3rd 2011, 01:54 AMmr fantasticRe: Factorise Equation
- Oct 3rd 2011, 02:01 AMgilagilaRe: Factorise Equation
- Oct 3rd 2011, 03:56 AMmr fantasticRe: Factorise Equation
- Oct 3rd 2011, 04:46 AMgilagilaRe: Factorise Equation
- Oct 3rd 2011, 05:05 AMCaptainBlackRe: Factorise Equation
- Oct 3rd 2011, 06:45 AMgilagilaRe: Factorise Equation
- Oct 3rd 2011, 12:51 PMmr fantasticRe: Factorise Equation
Oh come on! You were shown exactly how to do the question. You made a careless mistake and that was also pointed out to you. Fixing the error is simple - you were told exactly what to do. Sorry, but you have been given more than enough help here to get the final answer.

Fix the mistake, post your answer. - Oct 3rd 2011, 04:09 PMgilagilaRe: Factorise Equation
f(x)=2(x-3)(x+2)^2 + 2(x+2)(x-3)^3

=2ab^2 + 2ba^3 = 2ab(b+a^2)

=2(x-3)(x+2)[(x+2)+(x-3)^2]

**Factorise f(x) completely**

=2(x-3)(x+2)[(x+2)+(x-3)^2]

oops, sorry for the reply. Not noticed that I had changed the squared to cube, now I rectified.

Is it correct now ? - Oct 3rd 2011, 04:33 PMWilmerRe: Factorise Equation
- Oct 3rd 2011, 04:41 PMProve ItRe: Factorise Equation
- Oct 3rd 2011, 06:35 PMgilagilaRe: Factorise Equation
- Oct 3rd 2011, 06:38 PMProve ItRe: Factorise Equation