Finding length of the missing side

**vaironxxrd** · October 2nd 2011, 01:01 PM

Even though this is geometry it comes from my Algebra 2 class.

I believe that $2x+3$ is the With so I guess that I have to find the length?
Area : $2x^2+5x+3$

Area= L*W

Therefore $2x^2+5x+3= 2x+3$ = Length?

**pickslides** · October 2nd 2011, 01:04 PM

It should be $2x^2+5x+3= (2x+3)\times L$ now divide it out.

**Siron** · October 2nd 2011, 01:06 PM

You know the length of the rectangle is $2x+3$ and the area of the rectangle is $2x^2+5x+3$ that means the breadth of the rectangle has to look like $ax+b$ , therefore:
$(2x+3)\cdot(ax+b)=2x^2+5x+3$

Determine $a$ and $b$

**vaironxxrd** · October 2nd 2011, 02:31 PM

Originally Posted by pickslides

It should be $2x^2+5x+3= (2x+3)\times L$ now divide it out.

$2x^2=L-3x$ ?

**skeeter** · October 2nd 2011, 03:29 PM

pickslides said divide ...

$L = \frac{2x^2+5x+3}{2x+3}$

**vaironxxrd** · October 2nd 2011, 03:53 PM

Originally Posted by skeeter

pickslides said divide ...

$L = \frac{2x^2+5x+3}{2x+3}$

$L=\frac{2x^2+3x}{1}$ or $2x^2+3x$

**skeeter** · October 2nd 2011, 04:18 PM

go learn how to do long division of polynomials ...

Polynomial Long Division

**Quacky** · October 2nd 2011, 06:26 PM

Originally Posted by skeeter

go learn how to do long division of polynomials ...

Polynomial Long Division

Honestly I think Siron's method will suffice for now.

**skeeter** · October 3rd 2011, 03:02 AM

Originally Posted by Quacky

Honestly I think Siron's method will suffice for now.

if you had bothered to check the link, you would have noticed that it also shows the factoring technique.

**Quacky** · October 3rd 2011, 04:33 PM

Originally Posted by skeeter

if you had bothered to check the link, you would have noticed that it also shows the factoring technique.

I never denied that. But the subject of the page is on polynomial long division, and I think that's asking the OP to run before they walk. With the UK system, there are about 3 years of teaching between this, which is applying the knowledge of factoring, and polynomial division.

**Wilmer** · October 3rd 2011, 04:45 PM

Originally Posted by Quacky

Honestly I think Siron's method will suffice for now.

Well, NO method will suffice for now; the OP does not know basics and needs classroom help, period.

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