Solve for http://webwork.rutgers.edu/webwork2_...dd0b8b8e91.png:http://webwork.rutgers.edu/webwork2_...095126dd01.png

I know 9 is 3^2 and 4 is 2^2

but how can i simplify this while knowing the above?

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- Oct 2nd 2011, 11:02 AMhabibixoxExponents.
Solve for http://webwork.rutgers.edu/webwork2_...dd0b8b8e91.png:

http://webwork.rutgers.edu/webwork2_...095126dd01.png

I know 9 is 3^2 and 4 is 2^2

but how can i simplify this while knowing the above?

- Oct 2nd 2011, 11:05 AMSironRe: Exponents.
To make it easy you can take the of both sides and use and you can also use in the first place

- Oct 2nd 2011, 11:11 AMhabibixoxRe: Exponents.
so would it be

9x/3 log 9 = 8x/2 log 4 ? - Oct 2nd 2011, 11:15 AMSironRe: Exponents.
If you use the rule I suggested then you get:

- Oct 2nd 2011, 11:19 AMhabibixoxRe: Exponents.
ohh!!! ah oki i gotcha now :)

all the rules of exponents just confuse me!

thanks so much! do you mind taking a look at my half life problem i posted earlier? - Oct 2nd 2011, 11:41 AMSironRe: Exponents.
You're welcome! :)

To solve exponential equations then you really have to know this basic rules.