Hi there,

I am having difficulty getting the correct solution for

$\displaystyle \frac{1}{x^{2}-1}\div\frac{1}{x-1}=\frac{1}{x+1}$

I've been getting

$\displaystyle \frac{x-1}{x^{2}-1}$

which is as far as I can take it, I must be missing something simple.

Many thanks.