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Math Help - Problems..... Help

  1. #1
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    Problems..... Help

    26/57=849/5x
    Dont know how to do that!^^^^^^^
    And...
    4x+1/3=x-5/2
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by peachgal View Post
    4x+1/3=x-5/2
    is this \frac {4x + 1}{3} = \frac {x - 5}{2} or 4x + \frac {1}{3} = x - \frac {5}{2}?

    please use parentheses to clarify what you mean
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  3. #3
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    Quote Originally Posted by Jhevon View Post
    is this \frac {4x + 1}{3} = \frac {x - 5}{2} or 4x + \frac {1}{3} = x - \frac {5}{2}?

    please use parentheses to clarify what you mean
    Now I see how that could be confusing. It is:

    \frac {4x + 1}{3} = \frac {x - 5}{2}
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by peachgal View Post
    Now I see how that could be confusing. It is:

    \frac {4x + 1}{3} = \frac {x - 5}{2}
    we can cross multiply, do you know how?

    we get:

    \frac {4x + 1}{3} = \frac {x - 5}{2}

    \Rightarrow 3(x - 5) = 2(4x + 1)

    can you continue?

    a similar trick can be used for the first, but i wouldn't do it. it's simple enough not to use this trick. remember, our objective is to get x by itself on one side. so whatever is operating on the x, just perform the opposite operation on both sides of the equation to get rid of it
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  5. #5
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    Quote Originally Posted by Jhevon View Post
    we can cross multiply, do you know how?

    we get:

    \frac {4x + 1}{3} = \frac {x - 5}{2}

    \Rightarrow 3(x - 5) = 2(4x + 1)

    can you continue?

    a similar trick can be used for the first, but i wouldn't do it. it's simple enough not to use this trick. remember, our objective is to get x by itself on one side. so whatever is operating on the x, just perform the opposite operation on both sides of the equation to get rid of it
    YOU ARE THE BOMB! And really smart.... but I can't figure this one out I cant do algebra with division.

    26/57=849/5x

    And I tried to solve
    \frac {4x + 1}{3} = \frac {x - 5}{2}

    \Rightarrow 3(x - 5) = 2(4x + 1) but I get to this part and can't continue :

    3x-13/8=8x-8
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by peachgal View Post
    YOU ARE THE BOMB! And really smart.... but I can't figure this one out I cant do algebra with division.

    26/57=849/5x
    well, we can begin by flipping both sides:

    \frac {26}{57} = \frac {849}{5x}

    \Rightarrow \frac {57}{26} = \frac {5x}{849} = \frac {5}{849}x

    now i want to get to x, but there is a \frac 5{849} multiplying it, so what do i do? i divide both sides by \frac 5{849}, thus i obtain:

    x = \frac {57}{26} \cdot \frac {849}{5}

    now simplify



    And I tried to solve
    \frac {4x + 1}{3} = \frac {x - 5}{2}

    \Rightarrow 3(x - 5) = 2(4x + 1) but I get to this part and can't continue :

    3x-13/8=8x-8
    i don't see how you got to that

    what exactly are you doing here? explain your process
    Last edited by Jhevon; September 13th 2007 at 07:44 PM.
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  7. #7
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    [quote=Jhevon;69944]
    Quote Originally Posted by peachgal View Post
    YOU ARE THE BOMB! And really smart.... but I can't figure this one out I cant do algebra with division.

    26/57=849/5x

    well, we can begin by flipping both sides:

    \frac {26}{57} = \frac {849}{5x}

    \Rightarrow \frac {57}{26} = \frac {5x}{849} = \frac {5}{849}x

    now i want to get to x, but there is a \frac 5{849} multiplying it, so what do i do? i divide both sides by \frac 5{849}, thus i obtain:

    x = \frac {57}{26} \cdot \frac {849}{5}

    now simplify


    i don't see how you got to that

    what exactly are you doing here? explain your process
    This is what I did I think I'm wrong
    3(x-5)=2(4x+1)<br />
3x-15=8x-2<br />
+2<br />
3x-13/8=8x/8
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  8. #8
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by peachgal View Post

    This is what I did I think I'm wrong
    3(x-5)=2(4x+1)<br />
3x-15=8x-2<br />
+2<br />
3x-13/8=8x/8
    ok, that was even more confusing. you cannot have the equal signs all in line like that. add you can't have lines running into each other, as you clearly have. no wonder you're getting confused

    3(x - 5) = 2(4x + 1) ..........expand the brackets

    \Rightarrow 3x - 15 = 8x + 2 ...........get all the x's to one side

    \Rightarrow 8x - 3x = -15 - 2 ........simplify

    \Rightarrow 5x = -17 .....................divide both sides by 5

    \Rightarrow x = - \frac {17}{5}
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  9. #9
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    Quote Originally Posted by Jhevon View Post
    ok, that was even more confusing. you cannot have the equal signs all in line like that. add you can't have lines running into each other, as you clearly have. no wonder you're getting confused

    3(x - 5) = 2(4x + 1) ..........expand the brackets

    \Rightarrow 3x - 15 = 8x + 2 ...........get all the x's to one side

    \Rightarrow 8x - 3x = -15 - 2 ........simplify

    \Rightarrow 5x = -17 .....................divide both sides by 5

    \Rightarrow x = - \frac {17}{5}
    Right on! You are a life savior! May I ask what math you're in now?
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  10. #10
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by peachgal View Post
    Right on! You are a life savior! May I ask what math you're in now?
    not that it matters here, but i'm in a probability theory course (i'm a complete idiot when it comes to probability, i'm trying to change that) and an advanced calculus course


    This is my 35th post!!!!!!!
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  11. #11
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    Wow I'm 14 and soon to start algebra 2. Not near as smart as you...
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  12. #12
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by peachgal View Post
    Wow I'm 14 and soon to start algebra 2. Not near as smart as you...
    i'm not smart, just older. that's the only reason i'm ahead of you
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