Look again at reply #12.

Does that $\displaystyle h(x)$ work?

If so, why does it work? How does it work?

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- Oct 1st 2011, 01:40 PMPlatoRe: Combinations of Functions
- Oct 1st 2011, 01:54 PMBobRossRe: Combinations of Functions
Well when I input that $\displaystyle h(x)$ into $\displaystyle g(h(x))$, the answer is equal to the given $\displaystyle f(x)$, so it does work. I'm not sure how you got that $\displaystyle h(x)$ though.

- Oct 1st 2011, 02:01 PMPlatoRe: Combinations of Functions
- Oct 1st 2011, 02:06 PMBobRossRe: Combinations of Functions
Okay I think I've got it now. So I just need to look at the given values and decide what value of $\displaystyle h(x)$ will give me $\displaystyle f(x)$ when combined with $\displaystyle g(x)$? Thank you very much, you've been a huge help!