Is this right? Problem:$\displaystyle \frac{2x^2}{y}*\frac{3y}{3y^2}$ Attempt:$\displaystyle \frac{6x^2y}{3y^3}$
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Originally Posted by vaironxxrd Is this right? Problem:$\displaystyle \frac{2x^2}{y}*\frac{3y}{3y^2}$ Attempt:$\displaystyle \frac{6x^2y}{3y^3}$ And $\displaystyle \frac{6x^2y}{3y^3}=\frac{2x^2}{y^2}$
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