Quacky's Guide to Factoring a Quadratic

Quote:

Originally Posted by

**andyboy179** so would i use 7 and 1, for example would i do 7x-1= -7 (i know that wouldn't fit but is it the correct way of doing it?)

You have 3 and 1.

You have 7 and 1.

-Take one number from the top and one number from the bottom.

-Pair them together and multiply them.

-There will be 2 numbers left unselected.

-Pair them together and multiply them.

-See if you can add them or subtract them to obtain 4

-If you can, place each paired number in an opposite bracket. You know which values are "stuck" to a $\displaystyle y$ so then you just need to work out the signs.

Re: Quacky's Guide to Factoring a Quadratic

7-3=4 so that would be it and y= -7 or -3

Re: Quacky's Guide to Factoring a Quadratic

Quote:

Originally Posted by

**andyboy179** 7-3=4 so that would be it and y= -7 or -3

We know it's $\displaystyle (3y\pm~)(y\mp~)$

Finish it up. Which numbers go in which brackets? Read through what I said above again if you get confused.

Re: Quacky's Guide to Factoring a Quadratic

Re: Quacky's Guide to Factoring a Quadratic

actually it would be (3y - 7)(y + 1) = 0

y= 7/3 or -1