Solve for : Is what I'm doing against rules of math: 3^3 = log base 3 x 27 = log base 3 x 27= 3^x log 27 = x log 3 x = log 27/ log 3? x=3 I think that's wrong.
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$\displaystyle \log_3 (\log_3 x) = 3 $ $\displaystyle \log_3 x = 3^3 $ $\displaystyle x = (3^3)^3 $
Originally Posted by Amer $\displaystyle \log_3 (\log_3 x) = 3 $ $\displaystyle \log_3 x = 3^3 $ $\displaystyle x = (3^3)^3 $ I'm sure you mean $\displaystyle \displaystyle x = 3^{3^3}$...
An important distinction! $\displaystyle (3^3)^3= 9^3= 729$. $\displaystyle 3^{3^3}= 3^{27}= 7625597484987$!
Originally Posted by HallsofIvy An important distinction! $\displaystyle (3^3)^3= 9^3= 729$ Are you sure?
$\displaystyle (3^3)^3 = 3^9 = 19,683$
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