# Math Help - Binomial Theorem for (3n+ 1)^3

1. ## Binomial Theorem for (3n+ 1)^3

I'm a complete beginner at these:

Could someone please correct me if I'm wrong please (and show me where)....

Here goes:

(3n+1)^3 = (3n)^3 + 3(3n)^2 + 3(3n)^2 + 1

which would give me

= 3 (9n^3 + 6n^2) +1 is this correct?

2. Originally Posted by Natasha
I'm a complete beginner at these:

Could someone please correct me if I'm wrong please (and show me where)....

Here goes:

(3n+1)^3 = (3n)^3 + 3(3n)^2 + 3(3n)^2 + 1

which would give me

= 3 (9n^3 + 6n^2) +1 is this correct?

$(3n+1)^3 = (3n)^3 + 3(3n)^2 + 3(3n)1^2 + 1$
$(3n+1)^3 = (3n)^3 + 3(3n)^2 + 3(3n) + 1$

I have marked with red ^2 in your post because in theorem its b^2 and because b=1 then b^2 =1, you have put (ab)^2 or a^2.

3. thanks :-)