Factor this Equation: x^2 + 6y - y^2 - 9 I figure, re-arrange. x^2 - y^2 + 6y - 9 Group. (x^2 - y^2) + (6y - 9) Factor. (x-y)(x+y) + 3(2y - 3) Re-arrange. 3(2y-3) + (x-y)(x+y)
Follow Math Help Forum on Facebook and Google+
I wou have done $\displaystyle \begin{array}{l} x^2 - \left( {y^2 - 6y + 9} \right) \\ x^2 - \left( {y - 3} \right)^2 \\ \left( {x - y + 3} \right)\left( {x + y - 3} \right) \\ \end{array} $
What about this one? (x-1)^2 - 1 I know it's a^2 - b^2, but I can't lay it out. Help please? EDIT: Nevermind, got it.
$\displaystyle \left[ {\left( {x - 1} \right) - 1} \right]\left[ {\left( {x - 1} \right) + 1} \right]$ ??
View Tag Cloud