Thread: Simplifying exponents

Is this legal? e^(xc)=6 --> (e^(c))^x = 6

I need to find a number C such that e^(xc)=6.

Thanks,

You have

Using the sum of an infinite geometric series

Now simplify the LHS, you can then solve for

Thanks, i'm kinda stuck with trying to solve the problem still..

I know this: r = e^c and a = 1.

so

6 = 1/1-e^c --> 6 = (1-e^c)^-1 is that on the right track?

Yep, now just solve for c.