Is this legal? e^(xc)=6 --> (e^(c))^x = 6
I need to find a number C such that e^(xc)=6.
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Using the sum of an infinite geometric series
Now simplify the LHS, you can then solve for
Thanks, i'm kinda stuck with trying to solve the problem still..
I know this: r = e^c and a = 1.
6 = 1/1-e^c --> 6 = (1-e^c)^-1 is that on the right track?
Yep, now just solve for c.
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