Is this legal? e^(xc)=6 --> (e^(c))^x = 6

I need to find a number C such that e^(xc)=6.

Thanks,

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- Sep 27th 2011, 06:20 PMl flipboi lSimplifying exponents
Is this legal? e^(xc)=6 --> (e^(c))^x = 6

I need to find a number C such that e^(xc)=6.

Thanks, - Sep 27th 2011, 06:43 PMpickslidesRe: Simplifying exponents
You have $\displaystyle 1+e^c+e^{2c}+e^{3c}+\dots = 6$

Using the sum of an infinite geometric series $\displaystyle S_{\infty} = \frac{a}{1-r}$

Now simplify the LHS, you can then solve for $\displaystyle c$ - Sep 27th 2011, 08:01 PMl flipboi lRe: Simplifying exponents
Thanks, i'm kinda stuck with trying to solve the problem still..

I know this: r = e^c and a = 1.

so

6 = 1/1-e^c --> 6 = (1-e^c)^-1 is that on the right track? - Sep 27th 2011, 08:33 PMpickslidesRe: Simplifying exponents
Yep, now just solve for c.