Basic Algebra Problem - Is there a better way of solving this?

Re: Basic Algebra Problem - Is there a better way of solving this?

There is a shorter way, I think:

Let = total votes.

Then, from the question, we can rewrite each person's vote count in terms of

Amanda has

Belinda has

Daniel has

Cameron has

Adding these up, we get:

Once you know this, it should be simple to finish.

Re: Basic Algebra Problem - Is there a better way of solving this?

B's votes = A-50, D's votes = C-134

V = total votes

V = A + A-50 + C + C-134

V = 2A + 2C - 184

A = .35(V) ..... C = (3A + 644) / 7 [1]

C-134 = .12(V) ..... C = (6A + 2798) / 19 [2]

[1][2]: (3A + 644) / 7 = (6A + 2798) / 19

Solve: A = 490

Wrapup...

Re: Basic Algebra Problem - Is there a better way of solving this?

Hey Quacky and Wilmer... I just want to say thank you both very much for your help and I see where I was being in-efficient now.

Quacky I love your solution and realize now I could of made it easier by linking the total votes (x) = Ax, Bx, Cx, Dx like you did rather then to x = D which made them un-related hence my second calculation I had to do.

Wilmer your solution was more along the lines of what I was initially trying to do and I got up to the part where V = 2A + 2C - 184 (although I did V = 2A + 2D + 84). However I became stuck after that and so eventually went about it a different way. Seeing your solution I now know why I was stuck and it's simply because I haven't learnt enough algebra yet to understand what you're doing in [1] & [2] altho I get the final step when you solve [1] = [2] to get A = 490 (but not too sure how to solve that either). This could be fun tho. You've now given me something more to play with so I'm going to bookmark this page and return to it once I've learnt more algebra to see if I can figure out the remaining steps on my own and I'll post again if I get stuck.

Thanks again to both of you because you've both been a huge help :D