# Thread: Factoring, dividing and POI or polynomial

1. ## Factoring, dividing and POI or polynomial

For this, so far I factored it and did the long division thing and got 2x^2 - 2

How would I go about doing b)? how do i know what to sub in, etc.

2. ## Re: Factoring, dividing and POI or polynomial

What factor did you use in the denominator?

Have you considered continuing to factor the remaining expression?

Intersection with the y-axis is (0,f(0)). Don't ever find that curious again.

3. ## Re: Factoring, dividing and POI or polynomial

Originally Posted by TKHunny
What factor did you use in the denominator?

Have you considered continuing to factor the remaining expression?

Intersection with the y-axis is (0,f(0)). Don't ever find that curious again.
(x-3) was the common factor so i found a) which is 2x^2 - 2

What points should I sub in for b)

4. ## Re: Factoring, dividing and POI or polynomial

How did you find (x-3), since only f(1) = 0 ==> (x-1) was given?

You should not "sub in" any values for b). You should continue to factor the expression.

5. ## Re: Factoring, dividing and POI or polynomial

Originally Posted by TKHunny
How did you find (x-3), since only f(1) = 0 ==> (x-1) was given?

You should not "sub in" any values for b). You should continue to factor the expression.
Well i factored the original equation in a) and I got (2x^2 - 2)(x-3) so that's where the x-3 came from.

6. ## Re: Factoring, dividing and POI or polynomial

Originally Posted by YassAttack
Well i factored the original equation in a) and I got (2x^2 - 2)(x-3) so that's where the x-3 came from.
Even though this is a correct (though not complete) factorisation, you didn't follow the instructions you were given. You are expected to know that if f(a) = 0, then (x - a) is a factor. So being told that f(1) = 0, you should know that (x - 1) is a factor and that you are supposed to divide by (x - 1).

Assuming you have done that or if you want to continue with what you have done, now factorise the quadratic factor.