Thread: Another X in exponent question.

It states to to solve. The answer in the back of the book states that it's -1, 1. I just don't know where to start the questions.

3^(2x+1) - 10*3(^x)+3=0.

Oh by the way... how can I insert questions in proper format?

Thanks

Originally Posted by conpark

It states to to solve. The answer in the back of the book states that it's -1, 1. I just don't know where to start the questions.
3^(2x+1) - 10*3(^x)+3=0.

Rewrite that as .
Let solve

Originally Posted by conpark

3^(2x+1) - 10*3(^x)+3=0.
Oh by the way... how can I insert questions in proper format

You can learn to post in symbols, use LaTeX tags
[tex] 3^{2x+1} - 10\cdot 3^{x}+3=0 [/tex] gives

Just as a quick review, Plato is using " to change to and to change to .

Thanks everyone! Wish I had found this forum earlier. It would have saved me a lot of time~

HallsofIvy, is the solution simply 1 or -1 as well? I understand how to get one but the book states the solutions as -1 and 1, with the -1 listed first. Cheers

Nevermind. I got it.