It states to to solve. The answer in the back of the book states that it's -1, 1. I just don't know where to start the questions.
3^(2x+1) - 10*3(^x)+3=0.
Oh by the way... how can I insert questions in proper format?
Thanks
It states to to solve. The answer in the back of the book states that it's -1, 1. I just don't know where to start the questions.
3^(2x+1) - 10*3(^x)+3=0.
Oh by the way... how can I insert questions in proper format?
Thanks
You can learn to post in symbols, use LaTeX tags
[tex] 3^{2x+1} - 10\cdot 3^{x}+3=0 [/tex] gives
$\displaystyle 3^{2x+1} - 10\cdot 3^{x}+3=0 $
Just as a quick review, Plato is using "$\displaystyle a^{x+y}= a^xa^y$ to change $\displaystyle 3^{2x+1}$ to $\displaystyle 3^{2x}3^1= 3(3^{2x})$ and $\displaystyle a^{xy}= (a^x)^y$ to change $\displaystyle 3^{2x}$ to $\displaystyle (3^x)^2$.