How do I factor an equation like this: 7(x-3)^3 -2(x-3)^2 -5(x-3) ?
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Originally Posted by tmac20 How do I factor an equation like this: 7(x-3)^3 -2(x-3)^2 -5(x-3) Can you factor $\displaystyle 7y^3-2y^2-5y~?$ If so, let $\displaystyle y=(x-3).$
Originally Posted by Plato Can you factor $\displaystyle 7y^3-2y^2-5y~?$ If so, let $\displaystyle y=(x-3).$ Thanks, does this sound right: (x-3)[7(x-3)+5][(x-3)-1]
Originally Posted by tmac20 Thanks, does this sound right: $\displaystyle (x-3)[7(x-3)+5][(x-3)-1]$ $\displaystyle (x-3)[7(x-3)+5][(x-3)-1]=(x-3)(7x-16)(x-4)$
Originally Posted by Plato $\displaystyle (x-3)[7(x-3)+5][(x-3)-1]=(x-3)(7x-16)(x-4)$ Thanks, can you help with with one more problem: Factor: x^2 -8x-4y^2 +12-8y I've gotten this far: (x-6)(x-2) -4y(y+2) Can I factor even more from there?
Consider $\displaystyle x^2-8x-4y^2-8y+12$ as a quadratic expression in $\displaystyle x$, so use the quadratic formula to factore the expression.
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