Solving even and odd functions algebraically is what's kicking my butt at the moment. I have to, algebraically of course, determine if an equation is considered even, odd, or neither. But I need help on this question!
NEED! HELP!
Solving even and odd functions algebraically is what's kicking my butt at the moment. I have to, algebraically of course, determine if an equation is considered even, odd, or neither. But I need help on this question!
NEED! HELP!
no, it's not right. what you wrote makes no sense. you right f(x) and then you equate it to something that's not f(x) then you lose the square form the x in the denominator, that is just all types of wrong. i did several of these questions for you. examine them carefully and see what i did, i assure you, i did nothing of the sort that you did here
Okay, well. That's the reason why I wanted you to do a single problem step by step so I can see what I do wrong and whatnot. Because if I'm doing THIS single step wrong, all my answers are wrong, ya know?
So I'm learning the long way, why don't you just do this problem, and from what I learn, I'll do another problem?
Seem fair?
no it doesn't seem fair, and here's why. i actually did what you asked, i did several problems for you already, i tested for you, step by step. evidently it didn't help you. that's why i need you to do this on your own. look on all those that i have done before, if you get it wrong i will comment on it, if you get it correct i'll let you know
ALRIGHT! For some reason, it's giving me an error and it won't go through. But anyways! Moving on! f(-x) = -f(x), making it an Even Function. Right?
f(x) = \frac{x}{x^2 - 1}
f(-x) = \frac{-x}{-x^2 - 1} = \frac{-x}{x^2 - 1}
-f(x) = \frac{x}{x^2 - 1} = \frac{-x}{x^2 - 1}
Alright, I'm gonna go now. Gotta crash before I pass out right here on the keyboard. Thank you, Jhevon, for all your help and all you'll be doing for me in the future, because you're most likely gonna be the guy I'll turn to if I've got anymore questions.
Later everybody.