# Math Help - rearranging fractions part two

1. ## rearranging fractions part two

Hi,

I was hoping someone could explain why

3/√x + √x = 3/√x + √x.√x/√X

when then simplifies further to

3+x/√x

many thanks

2. ## Re: rearranging fractions part two

Notice that $\sqrt{x}\cdot \sqrt{x}=x$

3. ## Re: rearranging fractions part two

Hi Siron,

Thank you for your help. However I received an email message with a different reply to the one above.
Can you repost your original answer please

thanks

4. ## Re: rearranging fractions part two

Make the addition:
$\frac{3}{\sqrt{x}}+\sqrt{x}=$ $\frac{3}{\sqrt{x}}+\frac{\sqrt{x}\cdot \sqrt{x}}{\sqrt{x}}=\frac{3+x}{\sqrt{x}}$

Do you see the relation with my previous post? ...
And an e-mail, with what answer?