Hi,

I was hoping someone could explain why

3/√x + √x = 3/√x + √x.√x/√X

when then simplifies further to

3+x/√x

many thanks

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- Sep 23rd 2011, 12:16 AMplanetdomirearranging fractions part two
Hi,

I was hoping someone could explain why

3/√x + √x = 3/√x + √x.√x/√X

when then simplifies further to

3+x/√x

many thanks - Sep 23rd 2011, 01:48 AMSironRe: rearranging fractions part two
Notice that $\displaystyle \sqrt{x}\cdot \sqrt{x}=x$

- Sep 23rd 2011, 03:41 AMplanetdomiRe: rearranging fractions part two
Hi Siron,

Thank you for your help. However I received an email message with a different reply to the one above.

Can you repost your original answer please

thanks - Sep 23rd 2011, 03:45 AMSironRe: rearranging fractions part two
Make the addition:

$\displaystyle \frac{3}{\sqrt{x}}+\sqrt{x}=$$\displaystyle \frac{3}{\sqrt{x}}+\frac{\sqrt{x}\cdot \sqrt{x}}{\sqrt{x}}=\frac{3+x}{\sqrt{x}}$

Do you see the relation with my previous post? ...

And an e-mail, with what answer?