Re: Simple Linear equations

There are multiple ways of thinking about this, but I'll do it in the way, given your solution, that it was "intended to be done".

You can factor out an x in the numerator of the fraction. So we have

$\displaystyle (x-1) - \frac{x(x-1)}{x-1} = 0$

Then you can cancel to get

$\displaystyle (x-1)-x=0$

which implies

$\displaystyle -1=0$

Thus we have a contradiction, and there are no solutions.

Re: Simple Linear equations

thanks a lot for your answer so precise and fast, I often make careless mistakes ^^

+1 subscribe to your youtube channel :)

Re: Simple Linear equations

step 2 in your solution needs correction

$\displaystyle \frac{(x-1)^2-x^2+x}{x-1}$ = 0

but on solving it gives x = 1 which makes given equation undefined so no solution for it

Re: Simple Linear equations

Thank you very much, now I understand