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Math Help - Simplify #3

  1. #1
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    Exclamation Simplify #3

    If you rationalize the denominator of
    then you will get



    Ok for this I have tried to conjugate but i get lost in the denominator.

    would it be

    [(5x sq rt 5) - (3y sq rt 3)] / 125x^2 - 27 y ^2

    If so how would I get the square roots out of the numerator?
    Thanks
    Last edited by mr fantastic; September 21st 2011 at 06:06 PM. Reason: Title.
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  2. #2
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    Re: Simplify #3

    Write the fraction as

    1/[(5 √5)x - (3√ 3)y]

    Multiply numerator and denominator by [(5 √5)x + (3√ 3)y].
    Using the difference of squares formula, the denominator becomes [(5 √5)x] - [(3√ 3)y] = 125x - 27y
    so
    A = [(5 √5)x + (3√ 3)y] and B = 125x - 27y.


    is this true?
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  3. #3
    MHF Contributor Siron's Avatar
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    Re: Simplify #3

    Right!
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