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If you rationalize the denominator of
then you will get
Ok for this I have tried to conjugate but i get lost in the denominator.
would it be
[(5x sq rt 5) - (3y sq rt 3)] / 125x^2 - 27 y ^2
If so how would I get the square roots out of the numerator?
Thanks
Write the fraction as
1/[(5 √5)x - (3√ 3)y]
Multiply numerator and denominator by [(5 √5)x + (3√ 3)y].
Using the difference of squares formula, the denominator becomes [(5 √5)x]² - [(3√ 3)y]² = 125x² - 27y²
so
A = [(5 √5)x + (3√ 3)y] and B = 125x² - 27y².
is this true?
Right!