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Math Help - dividing fractions

  1. #1
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    dividing fractions

    this is a fraction (x-2)^2 over 4x^2-16 divided by 21x over 3x+6 how do you divide it and make it into its lowest terms?
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    Quote Originally Posted by blame_canada100 View Post
    this is a fraction (x-2)^2 over 4x^2-16 divided by 21x over 3x+6 how do you divide it and make it into its lowest terms?
    do you mean \frac {\frac {(x - 2)^2}{4x^2 - 16}}{\frac {21x}{3x + 6}} ?
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  3. #3
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    i mean (x-2)^2 over 4x^2-16 (thats one fraction) divided by 21x over 3x+6(thats another fraction)
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by blame_canada100 View Post
    i mean (x-2)^2 over 4x^2-16 (thats one fraction) divided by 21x over 3x+6(thats another fraction)
    umm, yes, that's what i have

    \frac {\frac {(x - 2)^2}{4x^2 - 16}}{\frac {21x}{3x + 6}} = \frac {(x - 2)^2}{4x^2 - 16} \div \frac {21x}{3x + 6}

    = \frac {(x - 2)^2}{4x^2 - 16} \cdot \frac {3x + 6}{21x}

    = \frac {(x - 2)^2}{4 \left( x^2 - 4 \right)} \cdot \frac {3(x + 2)}{21x}

    = \frac {(x - 2)^2}{4(x - 2)(x + 2)} \cdot \frac {3(x + 2)}{21x}

    Hopefully the rest is obvious to you. if not, it's ok, say so
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