Simplify (3x+2)^2 divided by (6x+4)/5

Question:

$\displaystyle (3x+2)^2$ divided by $\displaystyle (6x+4/5)$

My working:

$\displaystyle (3x+2)(3x+2)$ x $\displaystyle (5/2(3x+2)$

$\displaystyle (3x+2)$ x $\displaystyle 5/2$

Answer:

$\displaystyle 5(3x+2)/2$

Is the answer correct?

Thank you

Re: Simplify (3x+2)^2 divided by (6x+4)/5

Quote:

Originally Posted by

**FailInMaths** Question:

$\displaystyle (3x+2)^2$ divided by $\displaystyle (6x+4/5)$

My working:

$\displaystyle (3x+2)(3x+2)$ x $\displaystyle (5/2(3x+2)$

$\displaystyle (3x+2)$ x $\displaystyle 5/2$

Answer:

$\displaystyle \frac{5(3x+2)}{2}$

Is the answer correct?

[TEX]\frac{5(3x+2)}{2}[/TEX] gives $\displaystyle \frac{5(3x+2)}{2}$ which is correct.

Re: Simplify (3x+2)^2 divided by (6x+4)/5

Quote:

Originally Posted by

**Plato** [TEX]\frac{5(3x+2)}{2}[/TEX] gives $\displaystyle \frac{5(3x+2)}{2}$ which is correct.

Thank you! =)