Given : mx^2 - 2(m-1)x +m -7 = 0 where m is non-zero parameter

1) calculate m so that the roots of the equation exist

2)calculate m so that the roots of the equation are opposite

3)can these roots be reciprocals ?(Punch)

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- Sep 21st 2011, 05:56 AMlebanonequation of second degree
Given : mx^2 - 2(m-1)x +m -7 = 0 where m is non-zero parameter

1) calculate m so that the roots of the equation exist

2)calculate m so that the roots of the equation are opposite

3)can these roots be reciprocals ?(Punch) - Sep 21st 2011, 06:23 AMHallsofIvyRe: equation of second degree
Something missing isn't there? What have you done yourself on this?

(An "equation of second degree" is also called a "quadratic equation". Do you know the quadratic formula?) - Sep 21st 2011, 06:29 AMlebanonRe: equation of second degree
no what quadratic equation , can you solve it plz

- Sep 21st 2011, 06:30 AMSironRe: equation of second degree
When does the roots of a quadratic equation exist, if the discriminant D ... 0? (<,>,=)