I ran this equation

$\displaystyle 112u^8+56u^4 v^4+3v^8=48u^8+24u^4 v^4+3v^8$

solving for $\displaystyle v$

through

http://www.quickmath.com/webMathematica3/quickmath/equations/solve/basic.jsp#v1=3v^8%2B24u^4+v^4%2B48u^8%3D3v^8%2B56u ^4+v^4%2B112u^8&v2=u
and am confused about it's results. It says that 2 of the values for $\displaystyle u$ are real. Here's one of them (sorry, I couldn't get the indices small with tex so am just using ordinary text

v=(-1)^(1/4) * 2^(1/4) * u

I don't understand how (-1)^(1/4) is real. I thought it was the same as $\displaystyle \sqrt{i}$

[edit]

Forgot to add, I've also done this by hand and have $\displaystyle 2u^4=-v^4$ which I think comes to the same thing.